org.springframework.web.servlet.DispatcherServlet noHandlerFound
No mapping found for HTTP request with URI [/] in DispatcherServlet with name
在配置SpringMVC环境时,常常出现访问的URL出错,报404错误,如果URL确定正确的话,通常都是我们配置错误
出现这个问题,毫无疑问,是我们配置错了
主要的错误处在两处,第一就是web.xml,完整的代码如下,仅作参考
<?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3.0.xsd" metadata-complete="true" version="3.0"> <context-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:application-context.xml</param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <filter> <filter-name>encodingFilter</filter-name> <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class> <init-param> <param-name>encoding</param-name> <param-value>UTF-8</param-value> </init-param> <init-param> <param-name>forceEncoding</param-name> <param-value>true</param-value> </init-param> </filter> <filter-mapping> <filter-name>encodingFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <servlet> <servlet-name>Workflow</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:Workflow-servlet.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Workflow</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <welcome-file-list> <welcome-file>index.html</welcome-file> </welcome-file-list> </web-app>
需要注意上面的*.do 您也可以更改为 /
第二个问题,也是比较奇怪的问题,像我上面配置,就需要在Workflow-servlet.xml 添加一个静态资源,如果没有
<!-- 静态资源不过滤直接访问,否则图片等资源无法访问 web.xml,已配置拦截 .do 所以这里可不需要,如果添加任然有效 --> <mvc:resources location="/WEB-INF/resource/" mapping="res/**/**.**" />
自此,问题解决
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